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-0.14x^2+5.6x-7=0
a = -0.14; b = 5.6; c = -7;
Δ = b2-4ac
Δ = 5.62-4·(-0.14)·(-7)
Δ = 27.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.6)-\sqrt{27.44}}{2*-0.14}=\frac{-5.6-\sqrt{27.44}}{-0.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.6)+\sqrt{27.44}}{2*-0.14}=\frac{-5.6+\sqrt{27.44}}{-0.28} $
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